1.68t^2+8.68t-142.2=0

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Solution for 1.68t^2+8.68t-142.2=0 equation: 



1.68t^2+8.68t-142.2=0

a = 1.68; b = 8.68; c = -142.2;
Δ = b2-4ac
Δ = 8.682-4·1.68·(-142.2)
Δ = 1030.9264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8.68)-\sqrt{1030.9264}}{2*1.68}=\frac{-8.68-\sqrt{1030.9264}}{3.36}
$


$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8.68)+\sqrt{1030.9264}}{2*1.68}=\frac{-8.68+\sqrt{1030.9264}}{3.36}
$

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